Pointer Good Basic

It will clear the confusion about the pointer when arises.

Sum clear:

example code:

#include<stdio.h>
int main()
{
    int a,b,c;
    int *pa,*pb,*pc;
    a=10;
    b=40;
    pa=&a;
    pb=&b;
    pc=&c;

    *pc=*pb+*pa;

    printf("Sum = %d",*pc);

    return 0;
}

Array and Pointer:

#include<stdio.h>
int main()
{
    int a[5],i;
    printf("Enter 5 integer:\n");
    for(i=0;i<=4;i++)
    {
        scanf("%d",&a[i]);

    }
    printf("Array elements are:\n");
    for(i=0;i<=4;i++)
    {
        printf("array=%d\n pointer=%d\n",a[i],*(a+i));
    }
    return 0;
}

Array is nothing but a pointer:

#include<stdio.h>
int main()
{
    int a[5],i;
    printf("Enter 5 integer:\n");
    for(i=0;i<=4;i++)
    {
        scanf("%d",&a[i]);

    }
    printf("Array elements are:\n");
    for(i=0;i<=4;i++)
    {
        printf("address=%X \n array=%d\n pointer=%d\n",a+i,a[i],*(a+i));
        printf("arrayulta=%d\n pointerulta=%d\n",i[a],*(i+a));
    }
    return 0;
}

another variable pointer example:

#include<stdio.h>
int main()
{
    int a[5],i,*p;
    printf("Enter 5 integer:\n");
    for(i=0;i<=4;i++)
    {
        scanf("%d",&a[i]);

    }
    printf("Array elements are:\n");
    p=a;
    for(i=0;i<=4;i++)
    {
        
        printf("punga= %d %d %d %d\n",p[i],i[p],*(p+i),*(i+p));
    }
    return 0;
}

 

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Author: zakilive

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