Problem: The population of a town is given below as thousands
Year : 1891 1901 1911 1921 1931
Population : 46 66 81 93 101
Find the population of 1895 ?
Code:
#include<stdio.h> #include<math.h> #include<stdlib.h> main() { float x[20],y[20],f,s,d,h,p; int j,i,k,n; printf("enter the value of the elements :"); scanf("%d",&n); printf("enter the value of x:\n"); for(i=1;i<=n;i++) { scanf("%f",&x[i]); } printf("enter the value of y:\n"); for(i=1;i<=n;i++) { scanf("%f",&y[i]); } h=x[2]-x[1]; printf("enter the searching point f:"); scanf("%f",&f); s=(f-x[n])/h; d=y[n]; p=1; for(i=n,k=1;i>=1,k<n;i--,k++) { for(j=n;j>=1;j--) { y[j]=y[j]-y[j-1]; } p=p*(s+k-1)/k; d=d+p*y[n]; } printf("for f=%f ,ans is=%f",f,d); getch(); }
Output: