Tag Archives: c code bisection method

C code for bisection method

The Bisection Method is a numerical method for estimating the roots of a polynomial f(x). It is one of the simplest and most reliable but it is not the fastest method.
Problem: Here we have to find root for the polynomial x^3+x^2-1
Solution in C:

Algorithm:

1. Start
*Here a1 and b1 are initial guesses
TOL is the absolute error or tolerance i.e. the desired degree of accuracy*
3. Compute: f1 = f(a1) and f3 = f(b1)
4. If (f1*f3) > 0, then display initial guesses are wrong and goto step 11
Otherwise continue.
5. root = (a1 + b1)/2
6. If [ (a1 – b1)/root ] < TOL , then display root and goto step 11
* Here [ ] refers to the modulus sign. *
or f(root)=0 then display root
7. Else, f2 = f(root)
8. If (f1*f2) < 0, then b1=root
9. Else if (f2*f3)<0 then a1=root
10. else goto step 5
*Now the loop continues with new values.*
11. Stop

Output: Another Problem Solving Code:
Problem:
Here we have to find root for the polynomial x^3+x^2-1 upto 4D

Output: C code for bisection method

The Bisection Method is a numerical method for estimating the roots of a polynomial f(x). It is one of the simplest and most reliable but it is not the fastest method.
Problem: Here we have to find root for the polynomial x^3+x^2-1
Solution in C:

Algorithm:

1. Start
*Here a1 and b1 are initial guesses
TOL is the absolute error or tolerance i.e. the desired degree of accuracy*
3. Compute: f1 = f(a1) and f3 = f(b1)
4. If (f1*f3) > 0, then display initial guesses are wrong and goto step 11
Otherwise continue.
5. root = (a1 + b1)/2
6. If [ (a1 – b1)/root ] < TOL , then display root and goto step 11
* Here [ ] refers to the modulus sign. *
or f(root)=0 then display root
7. Else, f2 = f(root)
8. If (f1*f2) < 0, then b1=root
9. Else if (f2*f3)<0 then a1=root
10. else goto step 5
*Now the loop continues with new values.*
11. Stop

Output: Another Problem Solving Code:
Problem:
Here we have to find root for the polynomial x^3+x^2-1 upto 4D

Output: C code for bisection method

The Bisection Method is a numerical method for estimating the roots of a polynomial f(x). It is one of the simplest and most reliable but it is not the fastest method.
Problem: Here we have to find root for the polynomial x^3+x^2-1
Solution in C:

Algorithm:

1. Start
*Here a1 and b1 are initial guesses
TOL is the absolute error or tolerance i.e. the desired degree of accuracy*
3. Compute: f1 = f(a1) and f3 = f(b1)
4. If (f1*f3) > 0, then display initial guesses are wrong and goto step 11
Otherwise continue.
5. root = (a1 + b1)/2
6. If [ (a1 – b1)/root ] < TOL , then display root and goto step 11
* Here [ ] refers to the modulus sign. *
or f(root)=0 then display root
7. Else, f2 = f(root)
8. If (f1*f2) < 0, then b1=root
9. Else if (f2*f3)<0 then a1=root
10. else goto step 5
*Now the loop continues with new values.*
11. Stop

Output: Another Problem Solving Code:
Problem:
Here we have to find root for the polynomial x^3+x^2-1 upto 4D

Output: C code for bisection method

The Bisection Method is a numerical method for estimating the roots of a polynomial f(x). It is one of the simplest and most reliable but it is not the fastest method.
Problem: Here we have to find root for the polynomial x^3+x^2-1
Solution in C:

Algorithm:

1. Start
*Here a1 and b1 are initial guesses
TOL is the absolute error or tolerance i.e. the desired degree of accuracy*
3. Compute: f1 = f(a1) and f3 = f(b1)
4. If (f1*f3) > 0, then display initial guesses are wrong and goto step 11
Otherwise continue.
5. root = (a1 + b1)/2
6. If [ (a1 – b1)/root ] < TOL , then display root and goto step 11
* Here [ ] refers to the modulus sign. *
or f(root)=0 then display root
7. Else, f2 = f(root)
8. If (f1*f2) < 0, then b1=root
9. Else if (f2*f3)<0 then a1=root
10. else goto step 5
*Now the loop continues with new values.*
11. Stop

Output: Another Problem Solving Code:
Problem:
Here we have to find root for the polynomial x^3+x^2-1 upto 4D

Output: 