It’s possible with addition:
#include<iostream>
using namespace std;
int main(){
int x=10,y=15;
cout<<"Before swapping: x="<<x<<"y="<<y<<endl;
x=x+y; //25
y=x-y; //25-15=10
x=x-y; //25-10=15
cout<<"After swapping: x="<<x<<"y="<<y<<endl;
return 0;
}
It’s also possible with multiplication:
#include<iostream>
using namespace std;
int main(){
int x=10,y=15;
cout<<"Before swapping: x="<<x<<"y="<<y<<endl;
x=x*y; //25
y=x/y; //25-15=10
x=x/y; //25-10=15
cout<<"After swapping: x="<<x<<"y="<<y<<endl;
return 0;
}
Source:
http://www.geeksforgeeks.org/swap-two-numbers-without-using-temporary-variable/
